Otto Cycle Simulator
Interactive Otto cycle simulator with animated piston, P-V and T-S diagrams, compression ratio optimization, and thermal efficiency analysis. Learn how gasoline engines work with real-time visualization.
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Loading simulation, please waitOtto Cycle Simulator: Interactive Gasoline Engine Thermodynamics Calculator
✓ Verified Content: All equations, formulas, and reference data in this simulation have been verified by the Simulations4All engineering team against authoritative sources including MIT OpenCourseWare thermodynamics courses, NIST thermophysical properties, and Engineering Toolbox. See verification log
The Otto cycle simulator is an essential tool for understanding how gasoline engines convert chemical energy into mechanical work [1]. In this comprehensive guide, we'll explore thermodynamic engine cycles through our interactive Otto cycle calculator with real-time P-V diagrams, animated piston visualization, and efficiency analysis.
Introduction
Here's the efficiency gap that defines gasoline engine design: your car's engine burns fuel at roughly 2500 K peak temperature, yet typical thermal efficiencies hover around 25-30%. The second law tells us Carnot efficiency at those temperatures should approach 88%. Where does all that energy go? In practice, you lose energy to exhaust heat, cooling system rejection, friction, pumping losses, and the fundamental compromise of the Otto cycle's constant-volume combustion.
Energy in must equal energy out, plus whatever work you extract. In the Otto cycle, chemical energy from fuel combustion becomes internal energy of the gases, which then push the piston to produce mechanical work. Thermal engineers find that compression ratio is the single most powerful lever for improving efficiency. Raise it from 8:1 to 10:1 and you gain about 4 percentage points of efficiency. But push too high and knock destroys your engine.
No real Otto cycle achieves Carnot efficiency because constant-volume combustion is fundamentally less efficient than isothermal heat addition. You can't add heat at constant temperature in an IC engine because the fuel burns in a fraction of a millisecond while the piston barely moves. Experienced engine designers know this thermodynamic penalty is unavoidable, so they focus on maximizing compression ratio within knock limits and minimizing parasitic losses.
This interactive simulator allows you to explore the Otto cycle in real-time, visualizing the pressure-volume (P-V) and temperature-entropy (T-S) diagrams while animating the piston motion. You'll see how adjusting the compression ratio affects thermal efficiency and develop the energy accounting intuition that explains why modern engines squeeze every possible point of compression ratio from their fuel octane ratings.
How to Use This Simulation
Energy in must equal energy out. The chemical energy released during combustion becomes work extracted during expansion, plus heat rejected during exhaust. The second law tells us you cannot convert all heat to work: some must be rejected to the cold reservoir (exhaust gases).
Main Controls
| Control | Options | Purpose |
|---|---|---|
| Display Mode | P-V Diagram, T-S Diagram, Both | P-V shows work as enclosed area; T-S shows heat as area under process curves |
| Animation | Play Cycle, Step, Reset | Watch the four processes unfold. Step mode advances one process at a time to study each phase |
| Presets | Standard Engine, High Performance, Economy, Turbocharged | Loads typical compression ratios and temperatures for different engine types |
Input Parameters
| Parameter | Range | Units | Energy Accounting Note |
|---|---|---|---|
| Compression Ratio (r) | 4:1 to 14:1 | - | The single most important efficiency lever. η = 1 - 1/r^(γ-1). Higher r means more work from each fuel unit |
| Specific Heat Ratio (γ) | 1.20 to 1.67 | - | Air at room temp is ~1.4; combustion products drop toward 1.3. No real Otto cycle achieves ideal γ because combustion changes gas composition |
| Inlet Temperature (T₁) | 280 to 350 | K | Ambient intake conditions. Turbocharging raises this |
| Inlet Pressure (P₁) | 80 to 200 | kPa | Atmospheric or boosted. Forced induction increases this to pack more air-fuel mixture |
| Peak Temperature (T₃) | 1200 to 2500 | K | Maximum temperature after combustion. Limited by NOx formation and material constraints |
| Engine Displacement | 0.5 to 6.0 | L | Total swept volume. Affects absolute power but not efficiency |
| Engine Speed | 1000 to 8000 | RPM | Higher RPM means more power cycles per minute |
Output Display
The results panel tracks complete cycle performance:
- Thermal Efficiency (%): η = Wnet/Qin. Compare to Carnot at same temperature limits to see the efficiency gap
- Net Work Output (kJ/kg): Work per unit mass of air. Multiply by mass flow rate for power
- Heat Added Qin (kJ/kg): Energy released during constant-volume combustion (2→3)
- Heat Rejected Qout (kJ/kg): Energy carried away in exhaust (4→1). The second law says this cannot be zero
- MEP (kPa): Mean Effective Pressure. The constant pressure that would produce the same work over the swept volume
- Power @ RPM (kW): Absolute power at current engine speed
State Point Table
The detailed table shows properties at each corner of the cycle:
| State | Location | What Happens |
|---|---|---|
| 1 | Bottom Dead Center (intake complete) | Low P, low T, maximum volume |
| 2 | Top Dead Center (compression complete) | High P, elevated T, minimum volume. Isentropic compression: s₂ = s₁ |
| 3 | After combustion | Peak P, peak T, minimum volume. Constant volume heat addition: V₃ = V₂ |
| 4 | Bottom Dead Center (expansion complete) | Reduced P, still-hot T, maximum volume. Isentropic expansion: s₄ = s₃ |
Tips for Exploration
- Start at r = 8:1, Standard Engine preset: See the baseline efficiency around 56%. In practice, you lose energy to heat transfer, friction, and incomplete combustion, dropping real engines to 25-30%
- Increase compression ratio from 8:1 to 12:1: Watch efficiency climb from 56% to 63%. This is why engineers fight for every point of compression ratio
- See why high-performance engines use premium fuel: Higher octane allows higher r without knock. The efficiency gain justifies the fuel cost
- Compare γ = 1.4 (air) vs γ = 1.3 (combustion products): Efficiency drops because real combustion changes the working fluid properties
- Try the Turbocharged preset: Higher P₁ means more air-fuel mixture per cycle, more power from the same displacement
Why Otto Efficiency Tops Out
The Otto cycle efficiency formula η = 1 - 1/r^(γ-1) reveals the fundamental limits:
| Compression Ratio | Ideal η (γ=1.4) | Typical Real η | Loss Factors |
|---|---|---|---|
| 8:1 | 56% | 25% | Heat transfer, friction, pumping |
| 10:1 | 60% | 28% | Same losses apply |
| 12:1 | 63% | 30% | Knock limits further increase |
| 14:1 | 65% | N/A | Requires racing fuel or direct injection |
The gap between ideal and real comes from non-ideal compression/expansion, heat losses to cylinder walls, friction in bearings and piston rings, and pumping work during gas exchange.
Types of Thermodynamic Engine Cycles
Otto Cycle (Spark Ignition)
The Otto cycle models gasoline engines where combustion is initiated by a spark plug. Key characteristics include:
- Constant volume heat addition: Combustion occurs so rapidly that the piston doesn't move significantly
- Compression ratios: Typically 8:1 to 12:1, limited by knock
- Fuel: Gasoline with octane rating indicating knock resistance
- Applications: Passenger vehicles, motorcycles, small aircraft
Diesel Cycle (Compression Ignition)
The Diesel cycle models engines where fuel auto-ignites due to high compression temperatures:
- Constant pressure heat addition: Fuel is injected and burns as the piston moves
- Higher compression ratios: 15:1 to 22:1, enabled by no spark plug timing constraints
- Greater efficiency: Typically 40-45% vs 25-30% for gasoline engines
- Applications: Trucks, ships, locomotives, industrial equipment
Dual Cycle (Mixed)
Real diesel engines often follow a dual cycle combining constant volume and constant pressure combustion:
- More realistic model: Accounts for finite combustion duration
- Two heat addition phases: Initial rapid combustion, then continued injection
- Modern diesel engines: Computer-controlled injection timing
Atkinson and Miller Cycles
These modified Otto cycles improve efficiency through extended expansion:
- Atkinson: Expansion ratio greater than compression ratio via valve timing
- Miller: Similar concept using supercharging
- Hybrid vehicles: Toyota Prius uses Atkinson cycle for fuel efficiency
- Trade-off: Lower power density for higher efficiency
Key Parameters
| Parameter | Symbol | Units | Typical Range | Description |
|---|---|---|---|---|
| Compression Ratio | r | dimensionless | 8:1 - 14:1 | Ratio of maximum to minimum cylinder volume |
| Specific Heat Ratio | γ | dimensionless | 1.3 - 1.4 | cp/cv for the working fluid (air) |
| Thermal Efficiency | η | % | 45% - 65% | Fraction of heat converted to work |
| Mean Effective Pressure | MEP | kPa | 400 - 1200 | Equivalent constant pressure for work output |
| Heat Input | Q_in | kJ/kg | 500 - 1500 | Energy released during combustion |
| Net Work Output | W_net | kJ/kg | 300 - 800 | Useful work produced per cycle |
| Peak Temperature | T₃ | K | 1500 - 2500 | Maximum temperature after combustion |
| Peak Pressure | P₃ | MPa | 3 - 8 | Maximum pressure after combustion |
Key Formulas
Thermal Efficiency
Formula: η = 1 - 1/r^(γ-1)
Where:
- η = thermal efficiency (dimensionless)
- r = compression ratio (V₁/V₂)
- γ = specific heat ratio (cp/cv)
Used when: Calculating the ideal efficiency of an Otto cycle engine. This formula shows that efficiency depends only on compression ratio and working fluid properties, not on temperatures or heat input.
Isentropic Temperature Relation
Formula: T₂/T₁ = (V₁/V₂)^(γ-1) = r^(γ-1)
Where:
- T₁, T₂ = temperatures before and after compression
- V₁, V₂ = volumes before and after compression
- r = compression ratio
Used when: Calculating state changes during isentropic (adiabatic reversible) compression or expansion processes.
Isentropic Pressure Relation
Formula: P₂/P₁ = (V₁/V₂)^γ = r^γ
Where:
- P₁, P₂ = pressures before and after compression
- γ = specific heat ratio
Used when: Finding the pressure ratio across isentropic processes. Pressure rises more steeply than temperature during compression.
Heat Addition (Constant Volume)
Formula: Q_in = m·cv·(T₃ - T₂)
Where:
- Q_in = heat added during combustion
- m = mass of air
- cv = specific heat at constant volume
- T₂, T₃ = temperatures before and after combustion
Used when: Calculating energy input from fuel combustion, which occurs at constant volume in the Otto cycle.
Net Work Output
Formula: W_net = Q_in - Q_out = Q_in × η
Where:
- W_net = net work produced per cycle
- Q_out = heat rejected during exhaust
- η = thermal efficiency
Used when: Determining the useful work output from the engine, which is the area enclosed by the P-V diagram.
Mean Effective Pressure
Formula: MEP = W_net / (V₁ - V₂)
Where:
- MEP = mean effective pressure
- V₁ - V₂ = displacement volume
Used when: Comparing engines of different sizes. A larger MEP indicates a more effective engine design.
Learning Objectives
After completing this simulation, you will be able to:
- Calculate the thermal efficiency of an ideal Otto cycle given compression ratio and specific heat ratio
- Explain why higher compression ratios lead to better fuel efficiency and the practical limits imposed by knock
- Identify the four processes of the Otto cycle and describe the energy transfers in each
- Interpret P-V and T-S diagrams to understand the work output and heat flow in the cycle
- Compare the Otto cycle with Diesel and other engine cycles in terms of efficiency and applications
- Analyze how changing engine parameters affects power output, efficiency, and mean effective pressure
- Apply thermodynamic principles to real-world engine design and optimization problems
Exploration Activities
Activity 1: Compression Ratio Sensitivity Study
Objective: Understand how compression ratio affects thermal efficiency and identify the point of diminishing returns.
Steps:
- Set the compression ratio to the minimum value (4:1) and record the thermal efficiency
- Increase the compression ratio in steps of 1 and record efficiency at each point
- Create a plot of efficiency vs. compression ratio
- Identify where the curve begins to flatten (around r = 10-12)
- Calculate the efficiency gain from r = 8 to r = 10 versus from r = 10 to r = 12
Expected Results: Efficiency increases rapidly at low compression ratios but shows diminishing returns above r ≈ 10. This explains why modern engines target 10-12:1 ratios.
Activity 2: Engine Preset Comparison
Objective: Compare different engine configurations and understand design trade-offs.
Steps:
- Select the "Standard Engine" preset and record all state points and results
- Switch to "High Performance" and note the changes in T₃, efficiency, and power
- Compare with "Economy" preset - what was sacrificed for better fuel economy?
- Examine "Turbocharged" - how does increased inlet pressure (P₁) affect the cycle?
- Write a summary of the trade-offs each design makes
Expected Results: High-performance engines sacrifice some efficiency for power through higher peak temperatures. Economy engines reduce T₃ for better fuel economy. Turbocharging increases air density for more power.
Activity 3: Specific Heat Ratio Effects
Objective: Explore how working fluid properties affect cycle efficiency.
Steps:
- Keep compression ratio constant at r = 8
- Vary γ from 1.2 to 1.67 and observe efficiency changes
- Research which values correspond to different gases (air, exhaust, helium)
- Explain why real engines have lower efficiency than ideal - what happens to γ as temperature increases?
- Calculate the efficiency difference between γ = 1.4 (cold air) and γ = 1.3 (hot products)
Expected Results: Higher γ gives better efficiency. Real engines have lower γ during combustion due to high temperatures and combustion products, reducing actual efficiency below ideal predictions.
Activity 4: Power and Speed Analysis
Objective: Understand the relationship between engine speed, displacement, and power output.
Steps:
- Set a baseline configuration and note the power output
- Double the displacement (e.g., 2.0L to 4.0L) - what happens to power?
- Return to 2.0L and double the RPM - compare the power increase
- Find the combination that produces 100 kW of power
- Discuss why sports cars use high-revving small engines vs. trucks using large low-RPM engines
Expected Results: Power scales linearly with both displacement and RPM. High-revving engines are compact but stressed; large engines provide torque at low speeds.
Real-World Applications
Automotive Engineering
Passenger vehicles use Otto cycle engines ranging from 1.0L three-cylinder economy cars to 6.0L V12 sports cars. Engineers optimize compression ratio (10-13:1), valve timing, and fuel injection to balance power, efficiency, and emissions. Modern direct injection and variable valve timing allow Atkinson-like operation for better fuel economy.
Motorsports
Racing engines push Otto cycle limits with compression ratios up to 14:1, exotic fuels with high octane ratings, and extreme RPMs (18,000+ in F1). Understanding the thermodynamics helps engineers extract maximum power while preventing knock and mechanical failure.
Small Engine Applications
Lawn mowers, chainsaws, and portable generators use simplified Otto cycle engines. These applications prioritize reliability and low cost over maximum efficiency. Two-stroke variants combine intake/exhaust with power strokes for simpler construction.
Aircraft Piston Engines
General aviation aircraft use Otto cycle engines (Lycoming, Continental) with special considerations for altitude operation. Turbocharging maintains power as air density decreases, and specific fuel consumption is critical for range calculations.
Hybrid Vehicle Systems
Toyota's Synergy Drive uses Atkinson-cycle engines (modified Otto) for maximum efficiency at the expense of power. Electric motors supplement acceleration, allowing the combustion engine to operate in its most efficient regime.
Reference Data Tables
Air Properties at Various Temperatures
| Temperature (K) | γ (air) | cv (kJ/kg·K) | cp (kJ/kg·K) | Comment |
|---|---|---|---|---|
| 300 | 1.400 | 0.718 | 1.005 | Standard conditions |
| 500 | 1.391 | 0.742 | 1.032 | Compression temp |
| 1000 | 1.336 | 0.855 | 1.142 | Combustion products |
| 1500 | 1.299 | 0.953 | 1.238 | Peak temperature |
| 2000 | 1.274 | 1.023 | 1.304 | Extreme combustion |
Compression Ratio vs. Efficiency
| Compression Ratio | Efficiency (γ=1.4) | Efficiency (γ=1.3) | Typical Application |
|---|---|---|---|
| 6:1 | 51.2% | 43.1% | Old low-octane engines |
| 8:1 | 56.5% | 48.4% | Standard gasoline |
| 10:1 | 60.2% | 52.2% | Modern efficient engines |
| 12:1 | 63.0% | 55.1% | High-performance |
| 14:1 | 65.2% | 57.4% | Racing (special fuels) |
| 18:1 | 68.5% | 60.8% | Diesel engines |
Fuel Octane Ratings and Maximum Compression Ratios
| Fuel Type | RON | MON | Safe Max CR | Applications |
|---|---|---|---|---|
| Regular Gasoline | 87 | 82 | 9:1 | Economy vehicles |
| Premium Gasoline | 93 | 85 | 11:1 | Luxury/performance |
| Racing Gasoline | 100+ | 90+ | 13:1 | Motorsports |
| E85 (Ethanol Blend) | 105 | 89 | 12:1 | Flex-fuel vehicles |
| Aviation Gasoline | 100LL | - | 8.5:1 | Aircraft |
Challenge Questions
Level 1: Basic Understanding
-
If an Otto cycle has a compression ratio of 10:1 and γ = 1.4, what is its thermal efficiency?
-
Which process in the Otto cycle represents the combustion of fuel: 1→2, 2→3, 3→4, or 4→1?
Level 2: Intermediate Application
-
An engine has T₁ = 300 K and compression ratio r = 9. What is the temperature at the end of compression (T₂)?
-
If Q_in = 800 kJ/kg and the cycle efficiency is 56%, what is the net work output?
-
A turbocharged engine operates with inlet pressure P₁ = 150 kPa instead of 100 kPa. If all temperatures remain the same, how does this affect the net work output per kg of air?
Level 3: Advanced Analysis
-
Real engines achieve only about 50-60% of their ideal Otto cycle efficiency. List three major sources of irreversibility and estimate their relative impact.
-
Derive the expression for MEP in terms of compression ratio, inlet conditions, and heat input.
-
An engine designer wants to increase power by 20% without changing displacement. Compare the options of increasing compression ratio vs. increasing peak temperature, considering knock limits and material constraints.
Common Misconceptions
Misconception 1: "Compression ratio and pressure ratio are the same"
Reality: Compression ratio is V₁/V₂ (volume ratio), while pressure ratio P₂/P₁ = r^γ. For r = 8 and γ = 1.4, pressure ratio is 8^1.4 ≈ 18.4, not 8. The pressure rises much more than the volume decreases during compression.
Misconception 2: "Efficiency equals 1 - 1/r"
Reality: The correct formula is η = 1 - 1/r^(γ-1). The exponent (γ-1) is critical. With γ = 1.4, this is 0.4, making efficiency much higher than a simple reciprocal. Forgetting this exponent leads to significantly underestimating cycle efficiency.
Misconception 3: "γ stays constant at 1.4 throughout the cycle"
Reality: At high temperatures (>1000 K), γ decreases to ~1.25-1.3 due to molecular vibration modes becoming active. This reduces actual efficiency below ideal cold-air-standard predictions by 10-15%.
Misconception 4: "Real engines match ideal Otto cycle efficiency"
Reality: Real engines achieve only 50-60% of ideal efficiency due to friction, heat losses through cylinder walls, finite combustion time, pumping losses, and incomplete combustion. A 56% ideal efficiency translates to roughly 28-34% actual thermal efficiency.
Misconception 5: "The piston is stationary during constant-volume processes"
Reality: In real engines, combustion and exhaust valve events happen over finite time while the piston moves. "Constant volume" means the volume change is negligible compared to the speed of the thermodynamic process, not that the piston literally stops.
Misconception 6: "Higher compression ratio is always better"
Reality: Above ~12:1 (for regular 87-octane gasoline), auto-ignition (knock) occurs before the spark fires, causing destructive pressure waves in the cylinder. This is why octane rating matters and why high-performance engines require premium fuel.
Frequently Asked Questions
What is the thermal efficiency of an Otto cycle?
The thermal efficiency of an ideal Otto cycle is given by η = 1 - 1/r^(γ-1), where r is the compression ratio and γ is the specific heat ratio (approximately 1.4 for air) [1, 2]. For a typical gasoline engine with r = 10:1, the ideal efficiency is about 60%, though real engines achieve only 25-35% due to irreversibilities [3].
Why can't gasoline engines use higher compression ratios like diesel engines?
Gasoline engines are limited to compression ratios of about 10-12:1 because higher ratios cause the fuel-air mixture to auto-ignite before the spark plug fires, a phenomenon called "knock" or "detonation" [4, 5]. Diesel engines can use ratios of 15-22:1 because they inject fuel after compression, avoiding premature ignition.
What is the difference between Otto and Diesel cycles?
The Otto cycle uses constant-volume heat addition (instantaneous combustion at TDC), while the Diesel cycle uses constant-pressure heat addition (fuel injected and burned as the piston moves) [1]. At the same compression ratio, the Otto cycle has higher efficiency, but Diesel engines achieve higher efficiency in practice by using much higher compression ratios [2, 6].
How does turbocharging affect Otto cycle efficiency?
Turbocharging increases inlet pressure (P₁) and air density, allowing more fuel to be burned per cycle and increasing power output [5]. However, higher charge temperatures can increase knock tendency, so turbocharged engines often use lower compression ratios (8-9:1) and intercooling to compensate [7].
What is Mean Effective Pressure (MEP)?
MEP is a theoretical constant pressure that, if applied to the piston throughout the power stroke, would produce the same work as the actual cycle [1, 3]. It equals the net work divided by the displacement volume: MEP = W_net/(V₁-V₂). Higher MEP indicates a more effective engine design, with values typically ranging from 800-1200 kPa for naturally aspirated engines.
Why does the specific heat ratio (γ) decrease at high temperatures?
At higher temperatures, air molecules gain more vibrational degrees of freedom, increasing heat capacity and decreasing γ from 1.4 to about 1.25-1.3 [2, 8]. This reduces actual engine efficiency compared to ideal predictions that assume constant γ.
References and Further Reading
Open Educational Resources (Free Access)
-
MIT OpenCourseWare — 2.43 Advanced Thermodynamics. Available at: ocw.mit.edu — Free thermodynamics course covering power cycles
-
MIT OpenCourseWare — 2.60J Fundamentals of Advanced Energy Conversion. Available at: ocw.mit.edu — IC engine thermodynamics
-
OpenStax — University Physics Volume 2, Chapter 4: The Second Law of Thermodynamics. Available at: openstax.org — Free textbook, Creative Commons BY License
-
Khan Academy — Thermodynamics. Available at: khanacademy.org — Free video lectures on thermodynamic cycles
Data Sources (Free Access)
-
NIST Chemistry WebBook — Thermophysical Properties of Fluid Systems. Available at: webbook.nist.gov — Public domain thermodynamic property data
-
LibreTexts Engineering — Thermodynamic Cycles. Available at: eng.libretexts.org — Free reference data
-
HyperPhysics — Otto Engine. Georgia State University. Available at: hyperphysics.gsu.edu — Free educational resource
Historical Sources
- Otto, N.A. (1876) — Original patent for the four-stroke engine. Public domain historical reference
About the Data
All thermophysical property data used in this simulation (specific heat values, gas properties) are sourced from NIST Chemistry WebBook [5] and Engineering Toolbox [6]. The specific heat ratio values at various temperatures are based on NIST tabulated data.
Compression ratio limits are based on typical automotive industry values documented in MIT OpenCourseWare materials [1, 2] and HyperPhysics [7]. Efficiency calculations use the ideal air-standard Otto cycle assumptions: ideal gas behavior, constant specific heats (cold-air standard), and reversible processes.
Citation Guide
How to Cite This Simulation
APA Format: Simulations4All. (2025). Otto Cycle Simulator: Interactive Gasoline Engine Thermodynamics Calculator. Retrieved from https://simulations4all.com/simulations/otto-cycle-simulator
MLA Format: "Otto Cycle Simulator: Interactive Gasoline Engine Thermodynamics Calculator." Simulations4All, 2025, simulations4all.com/simulations/otto-cycle-simulator.
IEEE Format: Simulations4All, "Otto Cycle Simulator: Interactive Gasoline Engine Thermodynamics Calculator," 2025. [Online]. Available: https://simulations4all.com/simulations/otto-cycle-simulator
BibTeX:
@misc{simulations4all_otto_2025,
title = {Otto Cycle Simulator: Interactive Gasoline Engine Thermodynamics Calculator},
author = {{Simulations4All}},
year = {2025},
url = {https://simulations4all.com/simulations/otto-cycle-simulator},
note = {Interactive web-based thermodynamics simulation}
}
Verification Log
All scientific claims, formulas, and data have been verified against authoritative sources.
| Claim/Data | Source | Verification Status | Date Verified |
|---|---|---|---|
| Otto cycle efficiency: η = 1 - (1/r)^(γ-1) | MIT OCW 2.43, Engineering Toolbox | ✓ Verified | Dec 2025 |
| Isentropic relations: T₂/T₁ = (V₁/V₂)^(γ-1) | OpenStax University Physics Vol. 2 | ✓ Verified | Dec 2025 |
| Air specific heat ratio γ = 1.4 at STP | NIST Chemistry WebBook | ✓ Verified | Dec 2025 |
| Typical compression ratios: 8:1 to 12:1 | HyperPhysics, Georgia State University | ✓ Verified | Dec 2025 |
| Thermodynamic cycle processes | Engineering Toolbox | ✓ Verified | Dec 2025 |
| Ideal gas assumption for air-standard analysis | MIT OpenCourseWare 2.43 | ✓ Verified | Dec 2025 |
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